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What is the probability of drawing a king, queen an jack (not in order), with replacement, from a pack of cards
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When drawing any three cards from a standard deck, you have \(\dbinom{52}{3}\) total possible outcomes. In the deck you have 4 of each kings, queens, and jacks. The probability of drawing one king/queen/jack is \(\dfrac{\dbinom41}{\dbinom{52}1}\). The probability of drawing one each of a king, queen, and jack, is therefore \[\frac{\dbinom41\dbinom41\dbinom41}{\dbinom{52}3}\]
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