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Mathematics 18 Online
JoelTheBoss (joel_the_boss):

3x^32 + 8x^2 − 22x + 43 Same thing, I did one by myself but this one is tricky... @fakeee

JoelTheBoss (joel_the_boss):

Fresh if you see the boxes >_<

OpenStudy (anonymous):

refreshed... which is the initial function, and where do you want to shift it?

OpenStudy (anonymous):

you don't mean x^32, just x^3, right?

JoelTheBoss (joel_the_boss):

no, it says 32...\[3x^{32} + 8x^2 − 22x + 43\]

OpenStudy (anonymous):

yes that is the initial function, correct?

JoelTheBoss (joel_the_boss):

Yes.

OpenStudy (anonymous):

and where do you want to shift it?

JoelTheBoss (joel_the_boss):

Doesn't say, its asking for the end behavior.

OpenStudy (anonymous):

oh, sure:) ... lets label our definition: (dealing with only positive number a) and different (real) numbers c1, c2, c3, c4. AND, provided that: a>a1 a1>a2 a2>a3 for integer A's (all a1, a2, and on) only. \[\LARGE f(x)=({\large c_1})x^{\large a_1}+({\large c_2})x^{{\large a_2}}+...({\large c_3})\]

JoelTheBoss (joel_the_boss):

It is not necessary to graph this function in order to determine what will happen at the ends of a graph. Look at the degree of this function. The degree is 23, an odd number. This indicates that the ends of the graph will continue in opposite directions. Because the leading coefficient is positive, the left end will continue down and the right end will continue up. Correct?

OpenStudy (anonymous):

c1 is positive a1 is an odd number f(x) goes up to the right and down to the left. ---------------------------------------- c1 is negative a1 is an odd number f(x) goes down to the right and up to the left. ---------------------------------------- c1 is positive a1 is an even number f(x) goes up to the right and left. ---------------------------------------- c1 is negative a1 is an even number f(x) goes down to the right and left.

OpenStudy (anonymous):

no you don't need to graph... I posted the rules for function behaviours.

OpenStudy (anonymous):

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