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Algebra 8 Online
OpenStudy (anonymous):

Algebra 2 PLEASE HELP

OpenStudy (anonymous):

A ball is thrown vertically upward. After t seconds, its height h (in feet) is given by the function h(t)=88t-16t^2 What is the maximum height that the ball will reach? Do not round your answer.

OpenStudy (mathmath333):

first u need to differentiate the function with respect to \(t\) and equate it to \(0\)

OpenStudy (anonymous):

???????

OpenStudy (anonymous):

what?

OpenStudy (anonymous):

@mathmate

OpenStudy (mathmath333):

https://www.desmos.com/calculator/ql9vcs7oi1

OpenStudy (mathmate):

@mathgirl2012 I think you know how to find h'(t). Can you show what h'(t) is?

OpenStudy (anonymous):

I just want as many people as possible to help me

OpenStudy (anonymous):

I am completely lost?

OpenStudy (anonymous):

@mathmate

OpenStudy (mathmate):

@mathgirl2012 It is normal that you will get lost when multiple persons are helping you at the same time. It is ok to tag 2 or 3 people at the same time at the beginning. But refrain from doing so once someone starts helping you. By calling 5 other people \(while\) someone is helping you is a little insulting. You will lose your help, and perhaps others will lose interest in helping you in the future.

OpenStudy (anonymous):

sorry @mathmate

OpenStudy (mathmate):

@mathgirl2012 no problem for me. In correct etiquette, I should not even have posted when I see that others are helping you. However, I \(seemed\) to have detected a misunderstanding, that's why I intervened. Since others have lost interest in helping you, would you like to go back to your question?

OpenStudy (anonymous):

@mathmate can I ask you to come and help me on my next question

OpenStudy (mathmate):

@mathgirl2012 You're welcome to tag a couple of people, but try to avoid doing that when someone starts to help you, ok?

OpenStudy (mathmate):

To refresh my memory, can you tell me what have you done so far in algebra 2?

OpenStudy (mathmate):

* ...what you have done...

OpenStudy (mathmate):

@mathgirl2012 are you there?

OpenStudy (mathmate):

@mathgirl2012 Have you done completing the square?

OpenStudy (anonymous):

yes

OpenStudy (mathmate):

So if the maximum/minimum is at (3,3) Do you have a value for h in the general equation \(f(x)=a(x-h)^2+k\)

OpenStudy (mathmate):

|dw:1420214532026:dw|

OpenStudy (mathmate):

@mathgirl2012 See if you can find the values of (h,k) which define the vertex. We can then use the point (5,-5) to find the value of a.

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