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Mathematics 12 Online
OpenStudy (anonymous):

is this true or false?

OpenStudy (anonymous):

Question?

OpenStudy (anonymous):

OpenStudy (anonymous):

@Directrix @eliassaab @l

OpenStudy (anonymous):

@Michele_Laino

OpenStudy (anonymous):

@cwrw238

OpenStudy (cwrw238):

you need to differentiate twice - use the product rule

OpenStudy (cwrw238):

if u and v are functions of x then d(uv)/dx = u dv/dx + v du/dx

OpenStudy (michele_laino):

please apply the rule that @cwrw238 wrote, in order to calculate the first derivative! @familyguymath

OpenStudy (anonymous):

okat so what i got for the first derivative was (x^2)(-sinx) + (cosx)(2x)

OpenStudy (anonymous):

according to the product rule

OpenStudy (cwrw238):

yes thats correct

OpenStudy (cwrw238):

now apply the product again to each part

OpenStudy (anonymous):

then after this i knew that i had to find the second derivative so for each of the following parts (part a and part b) i knew i was going to have to apply the product rule to each part which i did and i got

OpenStudy (anonymous):

[(x^2)(cosx) + (sinx)(2x)] + [(cosx)(2) + (2x)(-sinx)]

OpenStudy (cwrw238):

the first part is wrong its -x^2 (cos x)

OpenStudy (cwrw238):

and second part is - 2x sinx

OpenStudy (anonymous):

yah i just checked my work and i realizied tht

OpenStudy (anonymous):

sorry so when simplifying the correct numbers it is true via [(x^2)(-cosx) + (-sinx)(2x)] + [(cosx)(2) + (2x)(-sinx)]

OpenStudy (cwrw238):

yes

OpenStudy (anonymous):

thanks for the help :)

OpenStudy (cwrw238):

yw

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