Question

For which operations is the set {–1, 0, 1} closed?

Choose all answers that are correct.

A.
addition

B.
division

C.
multiplication

D.
subtraction

Answer 1

@BPDlkeme234

Answer 2

@cwrw238

Answer 3

I think your answer its nt B, because \[\frac{ 1 }{ 0 }\]
is not dfine, so cannotbelongto your set

Answer 4

@paki

Answer 5

oops... is not defined, so it can not belong to your set

Answer 6

but any thing times and divid by 0=0 right

Answer 7

but you have to chose more than one

Answer 8

no, it is this:
\[\frac{ 0 }{ any-thing }=0\]

Answer 9

im confused?

Answer 10

for example:
what is \[\frac{ 0 }{ 5 }=0:5=...\]

Answer 11

0

Answer 12

so, 0:(any number)=0

Answer 13

hi @pielover123, this moves you into a new dimension

Answer 14

ok

Answer 15

how @BPDlkeme234

Answer 16

now I think that your answer can not D, since -1-(1)=-2, and -2 doesn't belong to your set

Answer 17

into the dimension of group theory

Answer 18

ok but there is more then one answer

Answer 19

oops..can not be D...

Answer 20

there are answer A and C

Answer 21

Which equations show that the set of whole numbers is closed under multiplication?

Choose all answers that are correct.

A.
–1 • –1 = 1

B.
0 • –1 = 0

C.
0 • 2 = 0

D.
2 • 1 = 2

Answer 22

for exmple A can be one of your answers

Answer 23

refresh if you see weird stuff

Answer 24

ok so a d for the las answer then right

Answer 25

*last

Answer 26

Let G be a set and x a binary operation on G. Then (G, x) is a group if the following properties hold:
G1 Closure: For all g, h element of G, g x h is an element of G

Answer 27

what

Answer 28

take the real numbers, if 2 numbers multiplied together still are parts of the real set then this is closure

Answer 29

sorry two real numbers

Answer 30

I think C and D, because a whole number is a number great or equal to zero

Answer 31

oops...greater or equal to zero...

Answer 32

the real question is do they remain in the same set of numbers (i.e closed)? since the original numbers are in the set of integers, that is what you need to ask! do the answers remain in the set of integers