A radio is being discounted 20%. If the sales price of the radio is $51.44, what was the original price of the radio? A. $12.86 B. $64.30 C. $41.15 D. 65.05 I know to multiply 51.44 by the percentage as a decimal then add it ( decimal= 0.2 ), but i get 61?
You can do a proportion: Example: If the sale price was $20, it is 80% of the original price and if $X is 100% of the original price, we write $20: 80% X=100% and solve for X by cross multiplication: X=\(\large \frac{$20*100\%}{80\%}\)=$25 (this is an example) You can apply the same method to your problem.
OHHH. okay thank you
@mathmate
hmm? im trying to apply it to my problem but it is diffitcult so i divide 51.44 by .80 i get 41.15, which is one of the choices but how could the original price be lower than the discount?
Or you can use algebra. Let x = original cost of radio then: .20x would equal the discount (20%) Sale price will equal original price Minus the discount OR 51.44 =x - .2x .8x = 51.44
thank you!
You're welcome, that is what we are here for.
It is B, thank you for your help!!
Did you follow with understanding. I forgot to mention that $51.44 was the "on sale" or discounted price.
@Kevinz You were almost there, but unfortunately you have multiplied by 0.8 instead of dividing. If you had made a division, you would have got $64.3 instead of $41.15. "there are different ways to skin a bear!"
@mathmate Yes thank you both, I learned that there was an inverse operation in this and that you could find the answer several ways.
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