Could someone please help me with this?:

Question

anonymous · Answer

Question?

anonymous · Answer

they are typing

superhelp101 · Answer

Ln2-ln(3x+2)=1

anonymous · Answer

mhmmm

anonymous · Answer

whats L and N for or are they just normal variables

superhelp101 · Answer

No sorry I meant natural logs

superhelp101 · Answer

I have to get a natural log on both sides of the equation although I forgot how to do that

anonymous · Answer

ah ok

anonymous · Answer

ignore that

superhelp101 · Answer

? do you know how I could get the logs on both sides and btw the answer is 4.125 well at least that is what my teacher got.

michele_laino · Answer

please note that if I apply the property of the logarithms with same base, I get:
$$\ln2-\ln(3x+1)=\ln \left( \frac{ 2 }{ 3x+1 } \right)$$
and if I apply the definition of logarithm I get:
$$1=\ln e$$

superhelp101 · Answer

I mean 4.214

superhelp101 · Answer

ohhhh I see

superhelp101 · Answer

@Michele_Laino what do I do after applying logs on both sides?

michele_laino · Answer

you have to equate both numbers, namely, from:
$$\ln \left( \frac{ 2 }{ 3x+1 } \right)=\ln e$$
we can write:
$$\frac{ 2 }{ 3x+1 }=e$$
so?

superhelp101 · Answer

would I multiply both of the sides by 3x+1 ?

superhelp101 · Answer

nvm I got how to solve it! 
thanks for all who came on the question and helped :)

michele_laino · Answer

Sorry I was at dinner
please multiply both sides by 3x+1