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Mathematics 21 Online
OpenStudy (anonymous):

Calculating sum help? How do I do this?

OpenStudy (anonymous):

OpenStudy (anonymous):

mhhh

OpenStudy (anonymous):

equally, its interesting!we like those questions here!

OpenStudy (anonymous):

interpretation: the sum from 1 to infinity of (x)^i

OpenStudy (turingtest):

the formula for a geometric sum is\[\sum_{i=0}^\infty ar^i=\frac a{1-r},~if~|r|<1\]notice that your sum starts at \(i=1\), so you will have to subtract off the value of i=0 to use the formula correctly

OpenStudy (anonymous):

so what do I use for a?

OpenStudy (anonymous):

@TuringTest

OpenStudy (turingtest):

what is the coefficient of the part that is being raised to i?

OpenStudy (anonymous):

@TuringTest .999

OpenStudy (turingtest):

no that is the base that is being raised to i what is the coefficient of that?

OpenStudy (anonymous):

oh, 1000?

OpenStudy (turingtest):

compare:\[\sum_1^\infty1000(0.999)^i\\\sum_0^\infty ar^i=\frac a{1-r}\]

OpenStudy (turingtest):

yes

OpenStudy (anonymous):

so plug in 1000 for a

OpenStudy (turingtest):

you need to make the series start at \(i=0\) first

OpenStudy (turingtest):

your starts at \(i=1\)

OpenStudy (turingtest):

yours*

OpenStudy (turingtest):

your series doesn't contain the term for \(i=0\), so you need to add that into the series, and subtract it again at the end what is the term of the series for \(i=0\) ?

OpenStudy (anonymous):

@TuringTest 1?

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