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Mathematics 18 Online
OpenStudy (anonymous):

Use basic identities to simplify the expression sinx cosx secx cscx

OpenStudy (anonymous):

opp = opposite adj = adjacent hyp = hypotenuse \[sin x = \frac{opp}{hyp}\]\[cos x = \frac{adj}{hyp}\]\[secx = \frac{hyp}{adj}\]\[cscx = \frac{hyp}{opp}\] so you are asking to simplify this really: \[ \frac{opp}{hyp} \times \frac{adj}{hyp} \times \frac{hyp}{adj} \times \frac{hyp}{opp}\]

OpenStudy (michele_laino):

since: (sin x)* (cosec x)=1 and (cos x)* (sec x==1 then your expression ie equal to ?

OpenStudy (campbell_st):

sec = 1/cos and csc = 1/sin so you have, with a little rearranging \[\sin \times \frac{1}{\sin} \times \cos \times \frac{1}{\cos} = ? \] you need to find the value of ?

Nnesha (nnesha):

\[\sin = \frac{ 1 }{ \csc }\] \[\cos = \frac{ 1 }{ \sec }\] \[\tan = \frac{ \sin }{ \cos }\] you should have to know this for trig \[\sec = \frac{ 1 }{ \cos }\] \[\csc = \frac{ 1 }{ \sin }\] \[\cot = \frac{\cos }{ \sin}\]

OpenStudy (anonymous):

Answers most be one of this: sec^2x csc^2x 1 tan^2x

Nnesha (nnesha):

okay so you have t o solve campbell_st<=== read what he did

Nnesha (nnesha):

you can change secx and cscx like cambell_st did cscx =1/sin so change csc to 1/sin

OpenStudy (anonymous):

Ok thanks, I get it now, the final answer is 1. Thanks once again!!!

Nnesha (nnesha):

yes right :)

Nnesha (nnesha):

my pleasure :)

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