An asteroid follows a hyperbolic path defined by the equation 16x^2 − 9y^2 = 576.
If one of its foci is the sun’s position, the minimum distance between the asteroid and the sun is(how many?) AU. (Note that x and y are expressed in astronomical units, AU.)
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OpenStudy (triciaal):
not a pro with these
related to a 3-4-5 triangle
do you happen to have choices?
OpenStudy (anonymous):
No I don't :(
OpenStudy (anonymous):
@iambatman can you help please?
OpenStudy (anonymous):
@ganeshie8 ?
OpenStudy (anonymous):
@TuringTest @wio
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OpenStudy (triciaal):
@jim_thompson5910 @Directrix @PRAETORIAN.10
ganeshie8 (ganeshie8):
As a start : change the given equation into standard form
\[\large \dfrac{x^2}{a^2} - \dfrac{y^2}{b^2}=1\]
ganeshie8 (ganeshie8):
divide both sides by 576 so that the right hand side becomes 1
OpenStudy (anonymous):
ok
OpenStudy (anonymous):
@Jhannybean
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ganeshie8 (ganeshie8):
\[16x^2 − 9y^2 = 576\]
dividing \(576\) through out you get
\[\dfrac{16x^2}{576} − \dfrac{9y^2}{576} = \dfrac{576}{576}\]
ganeshie8 (ganeshie8):
which is same as
\[\dfrac{x^2}{36} - \dfrac{y^2}{64} = 1\]
ganeshie8 (ganeshie8):
compare this with the standard form and see if you can eyeball the values of \(a\) and \(b\)
OpenStudy (anonymous):
6 & 8?
ganeshie8 (ganeshie8):
Yes!
a = 6
b = 8
so the x coordinate of vertex is 6
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ganeshie8 (ganeshie8):
Next find the x coordinate of focus by using the relation :
\[\large c^2 = a^2+b^2\]