An asteroid follows a hyperbolic path defined by the equation 16x^2 − 9y^2 = 576. If one of its foci is the sun’s position, the minimum distance between the asteroid and the sun is(how many?) AU. (Note that x and y are expressed in astronomical units, AU.)
not a pro with these related to a 3-4-5 triangle do you happen to have choices?
No I don't :(
@iambatman can you help please?
@ganeshie8 ?
@TuringTest @wio
@jim_thompson5910 @Directrix @PRAETORIAN.10
As a start : change the given equation into standard form \[\large \dfrac{x^2}{a^2} - \dfrac{y^2}{b^2}=1\]
divide both sides by 576 so that the right hand side becomes 1
ok
@Jhannybean
\[16x^2 − 9y^2 = 576\] dividing \(576\) through out you get \[\dfrac{16x^2}{576} − \dfrac{9y^2}{576} = \dfrac{576}{576}\]
which is same as \[\dfrac{x^2}{36} - \dfrac{y^2}{64} = 1\]
compare this with the standard form and see if you can eyeball the values of \(a\) and \(b\)
6 & 8?
Yes! a = 6 b = 8 so the x coordinate of vertex is 6
Next find the x coordinate of focus by using the relation : \[\large c^2 = a^2+b^2\]
100
\[\large c^2 = a^2+b^2\] \[\large c^2 = 6^2+8^2\] \[\large c^2 = 100\] \[\large c = ?\]
10
correct!
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