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Mathematics 17 Online
OpenStudy (korosh23):

Math question! Factor this expression: X4 + 16 x2 + 256

OpenStudy (lasttccasey):

Are you familiar with decomposition or "reverse FOIL" methods.

OpenStudy (korosh23):

Decomposition, yes

OpenStudy (korosh23):

What did you find ?

OpenStudy (triciaal):

remember the one earlier with substitution where you learn how to factor by grouping? let u = x^2 the problem is now u2 + 16 u + 256

OpenStudy (korosh23):

Ya that is right.

OpenStudy (korosh23):

Thank you for reminding me :)

OpenStudy (lasttccasey):

Apologies for the delay, its more complicated than simple decomposition, there's that extra step in this one, exactly what triciaal just explained.

OpenStudy (korosh23):

Ok

OpenStudy (korosh23):

The problem is what number multiplies to give 256 and adds up to give 16?

OpenStudy (korosh23):

@lasttccasey what should I do, can you give me a hint?

OpenStudy (lasttccasey):

You'll probably end up with imaginary numbers for solutions to this one. Give me a minute on that unless @triciaal knows a better way?

OpenStudy (korosh23):

ok

OpenStudy (korosh23):

@triciaal , do you know 2 numbers that multiply to give 256 and add to give 16?

OpenStudy (korosh23):

I have the answer in my textbook. You can try to find the way. The answer is 16(x2-x+1)(x2+x+1)

OpenStudy (korosh23):

@lasttccasey did you come up with anything?

OpenStudy (lasttccasey):

Might be a stupid question but are we sure the equation we're trying to factor is:\[x^4+16x^2+256\]

OpenStudy (korosh23):

I factored that a little bit, but in my textbook it asked to factor this: 16(x2+1)^2-4(2x)^2

OpenStudy (korosh23):

My bad!

OpenStudy (korosh23):

I thought I did it correct, I did a little bit and then I got stuck at it. I might have did It wrong.

OpenStudy (korosh23):

This is the equation that we have to find: 16(x2+1)^2-4(2x)^2

OpenStudy (lasttccasey):

lol yea I'm getting \[16x^4+16x^2+16\]

OpenStudy (korosh23):

Ya it is confusing, but I guess I found an example similar to this question in my textbook. Anyway thanks for helping.

OpenStudy (lasttccasey):

You're welcome, good luck!

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