A sphere with a radius of 4.8 centimeters is carved out of a right cone with a base radius of 8 centimeters and a height of 15 centimeters. What is the approximate volume of the remaining portion of the cone in terms of pi
hint: think of the cross section of the cone as a triangle and the cross section of the sphere as a circle try to fit the circle into the triangle the best you can (max out the area of the circle based on the fixed triangle)
something like this http://mathcentral.uregina.ca/QQ/database/QQ.09.07/h/linnea1.1.gif
oh ok
129.32πcm3 147.46πcm3 172.54πcm3 194.68πcm3 the choices
pi not ?
what is the volume of the cone? what is the volume of the sphere?
168.89 for cone??
you're using this formula right? V = (1/3)*pi*r^2*h this is for the volume of a cone
1005.31
leave it in terms of pi
960pi
you should have 320pi not 960pi check your work again
Idid 1/3*8^2*15
oh i forgot to divide by 3
now use this formula to find the volume of the sphere V = (4/3)*pi*r^3 leave the volume in terms of pi
then you will do (volume of cone) - (volume of sphere)
542.06
I'm not getting that for the volume of the sphere
no thats what i got for vol. of cone- sphere
for vol. of sphere i got 147.46
so, (volume of cone) - (volume of sphere) = (320pi) - (147.456pi) = 172.544pi
ok
thanks!
np
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