Question

Perform the operations on complex numbers:
(5+2i) / (3+6i)

Answer 1

Multiply numerator and denominator with the complex conjugate of 3+6i

Answer 2

you know how to do that?

Answer 3

Yes, so multiply by (3-6i)?

Answer 4

correct

Answer 5

for the denominator, you can use
\(\Large (a+bi)(a-bi) = a^2+b^2\)

Answer 6

for the numerator, multiply the 2 factors out
\((5+2i)(3-6i) = ...\)

Answer 7

thank you! So the numerator is 15-12i?

Answer 8

@hartnn, you keep beating me to all of the questions! Lol

Answer 9

not actually...
\(\Large (5+2i)(3-6i) = 5\times 3 + 5\times (-6i)+(2i)\times 3+(2i)\times (-6i)\)

Answer 10

\(\large (5+2i)(3-6i) = 5\times 3 + 5\times (-6i)+(2i)\times 3+(2i)\times (-6i)\)

Answer 11

@Jamal5337
If you want, you can continue helping him/her :)

Answer 12

It's okay, I'm helping JonnyChewy now!

Answer 13

Thanks hartnn!

Answer 14

did you get the required answer? :)

Answer 15

oh and bdw

\(\huge \color{red}{\text{Welcome to Open Study}}\ddot\smile\)

Answer 16

Another approach: Convert the given complex numbers to polar form.
\[\large\frac{z}{w}=\frac{re^{i\alpha}}{se^{i\beta}}=\frac{r}{s}e^{i(\alpha-\beta)}\]