Question

Given the sample triangle below and the conditions : sin B =1/2, A= 20. find the hypotenuse of the triangle
A. SqaureRoot3/2
B. 40SqaureRoot3/2
C.2
D.40

Answer 1

try to do like the one I walked you through earlier . remember it's not hard.

Answer 2

This is a right triangle, so we can use the definition of sin from SOH CAH TOA:

Sin (of angle) = Opposite side / hypotenuse

Sin of angle B = 1/2 (from problem statement)

Sin of angle B = opposite / hypotenuse = b/c

We know therefore that b/c = 1/2, and we can use that with a = 20 and the Pythagorean theorem to find b and c.

Answer 3

Solve
bc=12
for b in terms of c. Then write out
a2+b2=c2
substitute in your value for b in terms of c on the left hand side, and the value of a=20 on the left hand side. You should then have an equation in terms only of c to solve, and the positive answer will be the length of the hypotenuse.

Answer 4

sorry its a^2 + b^2 = c^2

Answer 5

yea i know. but where did 12 come from?

Answer 6

SORRY ITS \[B/C = 1/2\]

Answer 7

ok then whats next?

Answer 8

set up your triangle
the hypotenuse is opposite the right angle
use pythagorean theorem c^2 = a^2 + b^2
sin is O/H

Answer 9

i have mentioned it in an above reply

Answer 10

@ChiefArnav the computer has been messing up.
I walked her through this earlier also.

Answer 11

hmmm
then i may leave it up to you?

Answer 12

but i think i walked her up the whole problem.

Answer 13

I get the A^2 + b^2 = c^2 thing but I dont get how I put b/c = 1/2 in that problem

Answer 14

@ChiefArnav no please finish, stay