A charge Q is at distance d=2a from the surface of a conducting sphere.Using the method of images find the charge density of 3a from the center and the angles θ=30 degrees and make a graphical presentation.
Answer : ri=d_i^2+〖(3a〗^2)-2di(2)cos⁡(30)
r=d_^2+ (3a^2)-2d(3a)cos⁡(30)
V=1/4пe( Q/(d_^2+ (3a^2)-2d(3a)cos⁡(30)) - Qi/(d_i^2+〖(3a〗^2)-2di(2)cos⁡(30))
BUT how can i do the graphical presentation?

Question

A charge Q is at distance d=2a from the surface of a conducting sphere.Using the method of images find the charge density of 3a from the center and the angles θ=30 degrees and make a graphical presentation.
Answer : ri=d_i^2+〖(3a〗^2)-2di(2)cos⁡(30)
r=d_^2+ (3a^2)-2d(3a)cos⁡(30)
V=1/4пe( Q/(d_^2+ (3a^2)-2d(3a)cos⁡(30))    - Qi/(d_i^2+〖(3a〗^2)-2di(2)cos⁡(30))
 BUT how can i do the graphical presentation?

anonymous · Answer

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