Question

Does somebody knows how to do the program "Hello World" on Dev C++ 5.8.3

#include /* run this program using the console pauser or add your own getch, system("pause") or input loop */ int main(int argc, char** argv) { return 0; } I tried to do follow the steps of the video, but i do not know how to start.

Answer 1

so where did you write this code?

Answer 2

in a text file or what?

Answer 3

I did not write it. It comes by default

Answer 4

project

Answer 5

you downloaded an application, right?
And when you open it you see this code?

Answer 6

did you download Dev C++ 5.8.3 ?

Answer 7

yes

Answer 8

and you open it and see that code?

Answer 9

is there a "run" button?
can you send a screenshot?

Answer 10

i did not really see it

Answer 11

can you send a screenshot maybe?

Answer 12

yes

Answer 13

give me a second

Answer 14

Can you see it well?

Answer 15

http://docs.intersystems.com/documentation/cache/2008_1/pdfs/GBCP.pdf

Answer 16

In which part of this pdf can i find it?

Answer 17

Hey guys, if this is C++, then you are doing the right thing. I suggest using a search engine and looking up special tutorials with examples on how to write a specific program such as "Hello World." I took a C++ course in my sophomore year.

def function():
print (x)

""" def function():
\t print(x)"""

so you can use this example I was given when I took a similar course.
Elle

Answer 18

I think you do not use print in C++

Answer 19

what happens when you hit the "execute" button?

Answer 20

it runs

Answer 21

yeah but how do i make it say "Hello World"?

Answer 22

i think you can just do
```
#include <iostream>

int main(void)
{
cout >> "Hello World!" >> endl;
return 0;
}
```

Answer 23

what does endl;, means?

Answer 24

Do you always need to end with semicolon?

Answer 25

endl; means "end line" and creates a newline character (\n), which is the same as hitting return on your keyboard. If you don't put endl; you won't get a new line for each thin you print. Try
```
#include <iostream>

int main(void)
{
cout >> "Hello World!" >> endl;
cout >> "I am Learning C++!" >> endl;
return 0;
}
```
versus
```
#include <iostream>

int main(void)
{
cout >> "Hello World!";
cout >> "I am Learning C++!";
return 0;
}
```
The semicolon tells the compiler (the thing that translates your code to 0's and 1's) that the line of code you were writing is finished, and that it needs to move on to the next line of code. Forgetting to put a semicolon can cause your code to throw an error, or much worse, to run differently than you expect without telling you there was a mistake!So yes, the semicolon is very important in languages like C++, but newer languages like Python don't have that.

Answer 26

Oops I wrote the streams backwards
```
#include <iostream>
using namespace std;

int main(void)
{
cout << "Hello World!" << endl;
cout << "I am Learning C++!" << endl;
return 0;
}
```
```
#include <iostream>
using namespace std;

int main(void)
{
cout << "Hello World!";
cout << "I am Learning C++!";
return 0;
}
```

Answer 27

ohh ok thanks.

Answer 28

So if you just put semicolon without including endl it prints in the same line?

Answer 29

even though the elements may be in different lines?

Answer 30

sorry i am an extremely new learner of c++

Answer 31

yes, if you don't put either `endl;` or the newline character `\n`, everything will print on the same line, regardless of where the lines of code are

Answer 32

ohh hey btw your code gave me this error

Answer 33

yes I wrote the streams backwards
they should go `<<` not `>>`
my mistake

Answer 34

oh I see, you also put `int main(void)` inside `int main(int argc, char* argv)`
you can only have *one* `main` function per program
the only code you should have on your screen is
```
#include <iostream>
using namespace std;

int main(void)
{
cout << "Hello World!" << endl;
cout << "I am Learning C++!" << endl;
return 0;
}
```

Answer 35

ohh cool it worked !!!

Answer 36

btw why you changed

int main(int argc, char** argv)

for

int main(void)?

Answer 37

Because it is simpler, and you aren't using the `argc` or `argv` parts. You will learn what those do later (they are for command line arguments), but the first twenty programs you write will not involve command line arguments, so that code is unnecessary.

Answer 38

ohh ok thanks a lot!!!! you are the best!!!!

Answer 39

welcome, happy to help!