Question

Cartesian coordinates in polar cordination.

Answer 1

what does that say, i dont speak german

Answer 2

translate the directions sie bitte

Answer 3

Cartesian coordinates in polar cordination.

Answer 4

only that

Answer 5

and z1 = -2 - 2j

Answer 6

yes that I know its simple but on the picture I have do red circle

Answer 7

there are steps of solution I mean b) that I dont understand

Answer 8

first thing I write it

Answer 9

ok show me work

Answer 10

\[\sqrt[3]{\sqrt{8e ^{-jpi/4}}}\]

\[\[\sqrt[3]{\sqrt{8e ^{-j7\pi/4}}}\]\]

Answer 11

Ok I dont understand why 7pi?

Answer 12

ok sorry the inst -7jpi/4 is 7jpi/4

Answer 13

ok they first changed z= -2-2j to polar form

Answer 14

r= sqrt( (-2)^2 + (-2) )
= sqrt(8)

Answer 15

ok I know

Answer 16

theta = arctan(-2/-2)
but its better to use the function atan(-2,-2) , since it knows what quadrant you are in

Answer 17

ok

Answer 18

I know all this but I mean only the step that I written.

Answer 19

\[\sqrt[3]{\sqrt{8e ^{-jpi/4}}}\]

\[\sqrt[3]{\sqrt{8e ^{7\pi/4}}}\]

only this step the 7pi appare I dont understand how?

Answer 20

one moment

Answer 21

\[re ^{j \theta} = re ^{j \theta+2\pi} \]

Answer 22

the same way
sin ( theta + 2pi ) = sin theta

Answer 23

ok but in this case when I add only 2pi I have then 2pi/4 or its wrong?

Answer 24

\[re ^{j(-\pi/4)} = re ^{j(-\pi/4+2\pi)}= re ^{j(7\pi/4)} \]

Answer 25

aok and why I must add 2pi?

Answer 26

you don't have to , but its good to have an angle between 0 and 2pi, so that its easy to identify it.

Answer 27

its a way of standardizing the angle.

Answer 28

we like to have positive angles between 0 and 2pi

Answer 29

a ok when I want to have a positive angle I must only add 2pi right?

Answer 30

right

Answer 31

add enough multiples of 2pi so that you have an angle between 0 and 2pi

Answer 32

ok only a other step from this exercise can u hep me?

Answer 33

yes

Answer 34

ok I write it thx

Answer 35

\[\sqrt[3]{\sqrt{8e ^{7\pi/4}}}=\[\sqrt{2}*e ^{j7\pi/12}\]

Answer 36

first I have thing that sqrt is 1/2 so I add 1/2*1/3=1/6 it is right?

Answer 37

ok no its no right

Answer 38

first step how I can arrive to only sqrt?

Answer 39

to one not only

Answer 40

you want to know how they went to the next step

Answer 41

yes