Question

factor 49n^2 + 56n + 7

Answer 1

\[49n^{2}+56n+7\]\[\text{find the greatest common factor of 49, 56 and 7}\]\[\text{so basically what single number can be multiplied}\]\[\text{by a certain other number to get each number?}\]

Answer 2

7

Answer 3

do you know what to do now then?

Answer 4

nope

Answer 5

how do you factor something mero?

Answer 6

(7n + something) (n +something)

Answer 7

well there is an easier way but that works too i guess\[\text{GCF}(\frac{49}{\text{GCF}}n^{2}+(\frac{56}{\text{GCF}})n+(\frac{7}{\text{GCF}})\]GCF means greatest common factor

Answer 8

then take out the stuff outside parentheses and factor the stuff inside.
the smaller the numbers the easier to solve mero~ o vo

Answer 9

how would you do that for this

Answer 10

i just explained that to you

Answer 11

no i know but for this example

Answer 12

ok. what's the GCF ?

Answer 13

is it 7

Answer 14

so replace "GCF" with 7 in the equation i gave you
then take out the 7 outside the parentheses and keep the equation inside the parentheses

Answer 15

7n^2 + 8n + 1

Answer 16

yes, \[7n^{2}+8n+1\]

Answer 17

can you solve now?

Answer 18

(7n + 1 ) (n + 1)

Answer 19

i'm kinda rusty with the actual factoring stuff when n^2 has a coefficient sorry

Answer 20

I got this:\[(7n+7)(n+1)\]