Ask your own question, for FREE!
Mathematics 8 Online
OpenStudy (anonymous):

Algebra help. Will give medal!!!

OpenStudy (anonymous):

3. The price of products may increase due to inflation and decrease due to depreciation. Luke is studying the change in the price of two products, A and B, over time. The price f(x) in dollars, of product A after x years is represented by the function below. Part A: Is the price of product A increasing or decreasing and by what percentage per year? Justify your answer. (5 points) Part B: The table below shows the price f(t), in dollars, of product B after t years: Which product recorded a greater percentage change in price over the previous year? Justify your answer. (5 points). Part A: Is the graph for increasing or decreasing? Justify your answer: It is increasing Part B: What is the average rate of change from year 1 to year 2? Convert this number into a percentage. Which product has a greater percentage change in price?

OpenStudy (anonymous):

@mathmath333 I still need help here?

OpenStudy (anonymous):

@TheSmartOne can you help me?

OpenStudy (solomonzelman):

I think some information is missing

TheSmartOne (thesmartone):

^^^^

OpenStudy (anonymous):

give me a sec

OpenStudy (anonymous):

F(x)=0.69(1.03)^x

OpenStudy (anonymous):

@TheSmartOne I found the function

OpenStudy (anonymous):

do you need the table too??

OpenStudy (mathmath333):

\(\large\tt \begin{align} \color{black}{ f(x)=0.69(1.03)^x \\~\\ =0.69(1+0.3)^x \\~\\ =0.69(1+0.3)^x \\~\\ =0.69(1+(\dfrac{\color{red}{30}}{100}))^x \\~\\ }\end{align}\) so it is increasing by \(30\%\) per year for part B ,table is missing

OpenStudy (anonymous):

|dw:1420408039604:dw| @mathstudent55 can you help me? @mathmath333

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!