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Simplify each expression. a. sqrt(7x^3) * sqrt(14x) b. (64)^-2/3
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\[64^{-\frac{2}{3}}=\frac{1}{\sqrt[3]{64}}\] is a start
actually \[64^{-\frac{2}{3}}=\frac{1}{\sqrt[3]{64}^2}\]
the cube root of 64 is 4, 4 squared is 16 finishes it off
And in the a. you can combine everything under one square root function.\[\sqrt{7x^3}\cdot \sqrt{14x} = \sqrt{ (7 \cdot 14)x^4}\]
the post for a. can be simplified |dw:1420347026850:dw|
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