Question

can anyone help me with my math problems please :)

Answer 1

please

Answer 2

the easy way

Answer 3

B is stupid, ignore it

Answer 4

3 goes in to 6 twice, so there should be a \(b^2\) outside, not a \(b\)

Answer 5

i.e. ignore D

Answer 6

oh ok so b is totally wrong

Answer 7

oh way way wrong

Answer 8

is it a

Answer 9

nope

Answer 10

oh c then

Answer 11

\[\sqrt[3]{128}=4\sqrt[2]{2}\]

Answer 12

yeah C is always a safe bet

Answer 13

ok thanks :)

Answer 14

Lol I love how you go about eliminating answer choices, @satellite73 . Quite amusing.

Answer 15

can you help me with a few more problems :) please

Answer 16

sure
deposit \(\$.25\) in the slot for another five minutes

Answer 17

@Jhannybean thanks !

Answer 18

wait really i have to pay :(

Answer 19

where do i pay?

Answer 20

\[2\sqrt{13}+2\times 7\sqrt{13}=2\sqrt{13}+14\sqrt{13}\] then combine like terms

Answer 21

just like \(2x+14x=16x\)

Answer 22

oh what a surprise another C

Answer 23

your smart really its C :D

Answer 24

lol imagine
deposit another \(\$.25\) please

Answer 25

ok i have 7 more problems i need help with do you can you help with them or not?

Answer 26

where do i pay tho lol

Answer 27

can you help me with this one satellite73?:0please :>