Question

Solve for x: (image in comments)
A. 1
B. 2 +- (sqrt11)/4
C. 5 5/16
D. 0
E. none of these.

I'm getting -1/4 so E? is this correct?

Answer 1

@MARC_ there is the image sorry

Answer 2

\[\sqrt[3]{x^3+4x-5}-x=0\]

Answer 3

when you cube bot sides you get
\[4x-5=0\] maklng \[x=\frac{5}{4}\]

Answer 4

\[\sqrt[3]{x^3+4x-5}=x\]

Answer 5

yup x=5/4

Answer 6

\[=x^2-x+\frac{ 11 }{ 16 }\]

Answer 7

oh 5/4 somehow i was getting -1/4. so it would still be E then?

Answer 8

nope

Answer 9

substitute x=5/4 into the second equation @clynnew

Answer 10

\[=(\frac{ 5 }{ 4 })^2-\frac{ 5 }{ 4 }+\frac{ 11 }{ 16 }\]

Answer 11

\[=\frac{ 25 }{ 16 }-\frac{ 5 }{ 4 }+\frac{ 11 }{ 16 }\]

Answer 12

can u do the rest @clynnew ?

Answer 13

yes. so it would be 1 then?

Answer 14

yes :) @clynnew

Answer 15

oh i see it. thank you :)

Answer 16

\(\bf\huge\color{#ff0000}{Y}\color{#ff2000}{o}\color{#ff4000}{u'}\color{#ff5f00}{r}\color{#ff7f00}{e}~\color{#ffaa00}{W}\color{#ffd400}{e}\color{#bfff00}{l}\color{#4600ff}{co}\color{#6800ff}{me}\color{#8b00ff}{!!!}\) @clynnew