Solve each system. In your work, identify the shape of the graph of each equation.
7x^2 + x^2 = 64
x + y = 4

Question

Solve each system. In your work, identify the shape of the graph of each equation.
7x^2 + x^2 = 64
x + y = 4

anonymous · Answer

Thanks! Can you help me?

misty1212 · Answer

$$7x^2 + x^2 = 64\ x + y = 4$$

misty1212 · Answer

i am going to assume it is a typo and really was 
$$7x^2 + y^2 = 64 \x + y = 4$$

misty1212 · Answer

if not please say so
otherwise 
$$x+y=4\iff y=4-x$$ solve 
$$7x^2+(4-x)^2=6$$

misty1212 · Answer

@DanJS  not to be argumentative, but 
$$ax^2+by^2=c$$ is certainly not a circle, less off course $a=b$

misty1212 · Answer

i would go ahead and solve $$7x^2+(4-x)^2=6$$ not worrying too much about the shapes

misty1212 · Answer

then again it does not have a solution
can you check the question again?

anonymous · Answer

@misty1212 the equations you posted are correct.

misty1212 · Answer

$$7x^2+(4-x)^2=64$$

misty1212 · Answer

solve that one, it is not hard, do you know how to do it?

anonymous · Answer

not really

misty1212 · Answer

multiply out first on the left

misty1212 · Answer

$$7x^2+x^2-8x+16=64$$ or 
$$8x^2-8x-48=0$$

misty1212 · Answer

divide all by 8 and get to 
$$x^2-x-6=0$$ then factor

anonymous · Answer

would it be $$(x - 3)(x + 2)?$$

misty1212 · Answer

yes

misty1212 · Answer

so $x=3,x=-2$ then find the corresponding $y$ values

anonymous · Answer

How'd you "multiply out"? Where'd the $$x^2, 8x, and 16 come from?$$

misty1212 · Answer

$$(4-x)^2=(4-x)(4-x)$$ etc

anonymous · Answer

Ohhhhh okay. How do i find the "corresponding y- values?"

misty1212 · Answer

plug in the x values in to the part that says $x+y=4$ and see what you get for $y$

anonymous · Answer

$$(3, 1) (-2, 6)$$