Question

IF AN EDGE OF A CUBE IS INCREASED BY 33%, BY HOW MUCH IS THE TOTAL SURFACE AREA INCREASED? PLEASE THANK YOU :)

Answer 1

\(\sf Surface\ area =6(edge)^2=6a^2\)
edge increase by 33%
\(\sf Surface\ area' =6(1.33a)^2= 6(1.76)a^2\)
\(\sf Surface\ area' - Surface\ area = 6(1.76)a^2-6a^2=4.56%\)

not sure though

Answer 2

*oops my bad!
last line should be: \(\sf Surface\ area' - Surface\ area = 6(1.76)a^2-6a^2=1.76-1=76 %\)

Answer 3

76%

Answer 4

thank you

Answer 5

not 100% sure if i'm right though

Answer 6

ok thank you again:)

Answer 7

np :)