Question

HELLLP!!!

Answer 1

With?

Answer 2

\[\sqrt[3]{8x^3-1}=2x-1\]

Answer 3

u want to solve it?

Answer 4

Yes, solve for x

Answer 5

well,find \( (3x-1)^3 \)

Answer 6

i guess there is a typo
isn't that ???
\[(2x-1)^3\]

Answer 7

@Nnesha , yes ;)

Answer 8

:) cool :)

Answer 9

u know it does equal to
\[8x^3 - 1 - 12x^2 + 6x\]

Answer 10

so the equation would be :
\[8x^3 - 1 = 8x^3 - 1 - 12x^2 + 6x\]

Answer 11

can u solve it now?

Answer 12

Wait, is it possible to simplify the cube root?

Answer 13

Into \[2x-1\]

Answer 14

u can use \( a^3 - b^3 = (a-b)(a^2 + b^2 - ab) \) but here it wouldn't help.

Answer 15

\[\sqrt[3]{8x^3-1}=2x-1\]\[(\sqrt[3]{8x^3-1})^3 = (2x-1)^3\]

Answer 16

\[8x^3-1 = (2x-1)^3\]\[(a-b)^3 = a^3 -b^3 -3ab(a-b)\]

Answer 17

@Jhannybean , i was writing as you're now writing ;D

Answer 18

Oh really? Haha I just saw it @PFEH.1999 :D

Answer 19

but no prob , u can continue ;)

Answer 20

\[(2x-1)^3 \\ = 8x^3 -1-3(2x)(-1)(2x-1) \\ = 8x^3-1+6x(2x-1) \\ = \boxed{8x^3-1+12x^2-6x}\]

Answer 21

Oop. i took \(b\) as \(-1\) instead of \(1\).

Answer 22

Correction: \(8x^3 -1-12x^2+6x\)

Answer 23

So you would have: \[8x^3-1= 8x^3 -1-12x^2+6x\]Just group all your like terms togethr and simplify.

Answer 24

okay

Answer 25

So let me know what you get, @science00000 :)

Answer 26

this is a way to expand \((2x-1)^3=(2x-1) (2x-1)^2\)

Answer 27

incase ur more comfortable with quadratic