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OpenStudy (anonymous):
OpenStudy (anonymous):
OpenStudy (anonymous):
find ad
OpenStudy (jhannybean):
Lets draw it out first.
OpenStudy (anonymous):
ac=12cm
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OpenStudy (jhannybean):
|dw:1420350026594:dw|
OpenStudy (jhannybean):
Ok, I am going to redraw triangle BCD.|dw:1420350275786:dw|
OpenStudy (jhannybean):
Using the pythagorean theorem, we can find CD
OpenStudy (anonymous):
ok
OpenStudy (jhannybean):
\[CD=\sqrt{(2\sqrt{34})^2-(6)^2}\]
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OpenStudy (jhannybean):
So what will you get for CD? :) @imasim
OpenStudy (anonymous):
i have no idea 345
OpenStudy (anonymous):
I DIDNT MEAN TO PUT THE NUMBERS MYBAD
OpenStudy (jhannybean):
Haha, no problem! Just solve this.
\(\color{blue}{\text{Originally Posted by}}\) @Jhannybean
\[CD=\sqrt{(2\sqrt{34})^2-(6)^2}\]
\(\color{blue}{\text{End of Quote}}\)
OpenStudy (anonymous):
how i dont know how
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OpenStudy (jhannybean):
Well, \((2\sqrt{34})^2 = (2)^2 \cdot (\sqrt{34})^2\)
when you square a square root, you get the term inside the square root. Always remember: \((\sqrt{x} \cdot \sqrt{x}) = x \implies x = \sqrt{x} \cdot \sqrt{x}\)
OpenStudy (jhannybean):
So plugging that in to your calculator, what do you get for that?