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Mathematics 6 Online
OpenStudy (anonymous):

help

OpenStudy (anonymous):

OpenStudy (anonymous):

OpenStudy (anonymous):

find ad

OpenStudy (jhannybean):

Lets draw it out first.

OpenStudy (anonymous):

ac=12cm

OpenStudy (jhannybean):

|dw:1420350026594:dw|

OpenStudy (jhannybean):

Ok, I am going to redraw triangle BCD.|dw:1420350275786:dw|

OpenStudy (jhannybean):

Using the pythagorean theorem, we can find CD

OpenStudy (anonymous):

ok

OpenStudy (jhannybean):

\[CD=\sqrt{(2\sqrt{34})^2-(6)^2}\]

OpenStudy (jhannybean):

So what will you get for CD? :) @imasim

OpenStudy (anonymous):

i have no idea 345

OpenStudy (anonymous):

I DIDNT MEAN TO PUT THE NUMBERS MYBAD

OpenStudy (jhannybean):

Haha, no problem! Just solve this. \(\color{blue}{\text{Originally Posted by}}\) @Jhannybean \[CD=\sqrt{(2\sqrt{34})^2-(6)^2}\] \(\color{blue}{\text{End of Quote}}\)

OpenStudy (anonymous):

how i dont know how

OpenStudy (jhannybean):

Well, \((2\sqrt{34})^2 = (2)^2 \cdot (\sqrt{34})^2\) when you square a square root, you get the term inside the square root. Always remember: \((\sqrt{x} \cdot \sqrt{x}) = x \implies x = \sqrt{x} \cdot \sqrt{x}\)

OpenStudy (jhannybean):

So plugging that in to your calculator, what do you get for that?

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