Question

True of False? @danJS
The sequence a(sub)n = 2, 4, 8, 16, 32, ... is the same as the sequence a1 = 2, a(sub)n = 2a(sub)n - 1.

Answer 1

\[a _{n} = 2a _{n-1}\]
?
u mean this?

Answer 2

Yes

Answer 3

\[a_{1} = 2, a _{n} = 2a _{n-1}\]

Answer 4

true ;) becaus the ratio betweem two partial in that sequence is 2 and the first one is 2,so it would be
2,2x2,(2x2)x2 , ...

Answer 5

Thanks, i think it's true too. Just had to check.

Answer 6

nice ;)

Answer 7

Sorry, just got here

Answer 8

@DanJS , what?

Answer 9

i was tagged in the question. just now arrived

Answer 10

solved ;)

Answer 11

right on, yeah it is just 2^(n+1) if you pull out a factor of 2, then you just take 1 off the n, or 2*2^(n)