Question

Solve each system. @danJS
x^2+y^2+2x+ 2y = 0
x^2+y^2+4x+6y+12 = 0

Answer 1

ill answer them for u

Answer 2

ok, thanks

Answer 3

for number 1 Simplify x2+2x+y2 + 2y

Answer 4

welcome

Answer 5

for integer solution answer is
x = -2, y = -2

Answer 6

Answer for 1 is x^2+2 x+y (y+2) = 0 when simplifyed okay

Answer 7

im doing number 2 now okay

Answer 8

ok

Answer 9

Integer soulution is
x = -3, y = -3

Answer 10

Answer is
(x+2)^2+(y+3)^2-1 = 0

Answer 11

thank you for your help!

Answer 12

welcome ohh medal plzz

Answer 13

need anything else?

Answer 14

well in order to get your answer you basically just have to simplify

Answer 15

an its easier from there

Answer 16

there are actually 2 intersection points

x = -2 and y = -2

x = -6/5, y = -12/5

Answer 17

So like, who's right?

Answer 18

Both we got the same answer basically