Question

URGENT!
To open these doors, you must match the number and type of solutions for the following two functions in standard form.
f(x) = x2 + 6x – 16
g(x) = x2 +6x + 1
Match the following descriptions of the solutions to each of the functions above.
Hint: they each have their own match.

Two real irrationals solutions
Two real rationals solutions

Answer 1

x^2

Answer 2

\[x^{2}\]

Answer 3

yes, that! thank you

Answer 4

@Joel_the_boss

Answer 5

find the value of the discriminant b^2 - 4ac
the a,b and c refer to the constants in the standard form
ax^2 + bx + c = 0

Answer 6

I honestly have no idea what any of that means. I'm on the verge of flunking math so.. do I just substitute in random numbers?

Answer 7

compare the frirst of your equations to the above atandard form

a x^2 + bx + c = 0
x^2 + 6x - 16 = 0

a = 1, b = 6 and c = -16

do you follow?

Answer 8

rogger that

Answer 9

right so now you plug these values into b^2 - 4ac

b^2 - 4ac = 6^2 - 4 * 1 * -16
= 36 + 64 = 100

Answer 10

okayyy

Answer 11

so the value is 100 which is a perfect square
which indicates that the equation has two real rational solutions

Answer 12

gotchya

Answer 13

now if you do the same with the second equation you ought to find that the value is a positive number but not a perfect sqaure meaning that there are 2 real irrational solutions

Answer 14

Wow, you are so lovely! thank you a million zillion times! you saved my life and you don't even know it<3 :)

Answer 15

yw

Answer 16

the other 2 values of the discriminant
negative - means the roots are non real (complex)
zero - roots are real and duplicate

Answer 17

Got it, thanks again :)