WILL MEDAL CHECK.. Given that the first 4 terms of a geometric sequence are 2, x, 32, and 128, find the second term, x.3 ... ( I think the second term would be 4, )

Question

asnaseer · Answer

Remember a geometric sequence is one where the ratio between successive terms in the sequence is the same.

With this in mind, what is the ratio between the last two terms?

i.e. what is: $\frac{128}{32}$

anonymous · Answer

is that 125 over 32?

asnaseer · Answer

128/32 - look at the last two terms of your sequence

anonymous · Answer

128/32 = 4

asnaseer · Answer

good - so now you know that you need to multiply by 4 to get to the next term

asnaseer · Answer

so what do you think x=?

anonymous · Answer

8

acxbox22 · Answer

32/4=x

asnaseer · Answer

perfect! well done! :)

anonymous · Answer

another : Given that the first 5 terms of a geometric sequence are 3, x, 12, y, and 48, find, x and y. Assume both x and y are positive.

triciaal · Answer

I just answered that

asnaseer · Answer

<<<--- please ask each question separately in the question area on your left

asnaseer · Answer

this helps each question remain in focus

triciaal · Answer

go back to it and respond to my question