Question

Is an equation still solvable if there are variables in the denominator? Isn't there a value for x that will make the denominator zero and then you can't divide by zero?

Answer 1

@satellite73

Answer 2

@SolomonZelman

Answer 3

oh wait forgot you suck at word problems nvm

Answer 4

lol

Answer 5

as long as the solution is not the number that makes the "bottom" zero, you are ok

Answer 6

iof course they are
\[\frac{2}{x}=3\] can be solved right?

Answer 7

that's true

Answer 8

if you have something like: \(\normalsize\color{royalblue}{ \frac{\LARGE 3}{\LARGE x}=0 }\) then you won't have solutions.

Answer 9

so basically I shouldn't choose a number that will make the denominator zero

Answer 10

But something like: \(\normalsize\color{royalblue}{ \frac{\LARGE 3}{\LARGE x}=4 }\)
(or whenever the other side is not a zero, if you have an \(\normalsize\color{royalblue}{ x }\) in the denominator, then there will be a solution)

Answer 11

ohhhhhhhhhhhhhhhhhhhhhh

Answer 12

ok I think I get it

Answer 13

I think

Answer 14

yeah kind of

Answer 15

yes, because: \(\normalsize\color{royalblue}{ \frac{\LARGE 3}{\LARGE x}=0 }\) is never true.

there is not x value that satisfies this statement

Answer 16

ok seems simple now, thanks

Answer 17

\(\normalsize\color{royalblue}{ \frac{\LARGE 3}{\LARGE x}=0 }\)

you can multiply both sides times x,
and then you get: \(\normalsize\color{royalblue}{ 3=0 }\)

Answer 18

it is either way false

Answer 19

ok yeah makes sense

Answer 20

:)