Question

How can i factor completely:
3x^2(2x-4)^2+x^3(20)(2x-4)(2)

Answer 1

\(\bf x^2(2x-4)^2+x^3(20)(2x-4)(2)
\\ \quad \\
\implies x^2(2x-4)(2x-4)\quad +\quad x^2x^1(2x-4)(20)(2)
\\ \quad \\
\implies {\color{brown}{ x^2(2x-4)(2)}}(x-2)\quad +\quad {\color{brown}{ x^2}}x^1{\color{brown}{ (2x-4)}}(20){\color{brown}{ (2)}}\)

what do you think?

Answer 2

another approach
use substitution first to make it easier to see
let u = x^2(2x-4)

Answer 3

@jdoe0001 did you forget about the first coefficient of 3 or where did it go?

Answer 4

@daisyarlene8 sorry no need to use substitution nothing to solve

Answer 5

unless = 0

Answer 6

ohhh yeah... sorta coefficient 3 went MIA =)