Is this system of equations consistent, inconsistent, or dependent? 4x-3y=15 7y-35=9 1/3x A. consistent B. inconsistent C. dependent D. inconsistent and dependent E. none of these
@DanJS can you help me? i'm leaning more towards D?
What are the definitions of each of those cases, that you know
Here is what i think: Inconsistent = no solutions to the system, no point (x,y) that satisfies both equations. They are Parallel lines. Dependent = There are infinitely many solutions to the system. This happens if both equations are the same line, they overlap at an infinite amount of points (x,y) Consistent = the lines cross at one point, and there is a unique solution (x,y) that satisfies the equations.
That sound about good?
yes, those are basically the same definition to what i have written.
Just by those responses, without considering the equations, i think we can rule out D, i dont think it can be dependent and inconsistent at the same time can it?
And it has to be one of those 3 cases i think, i cant think of a system that is not one of the three, so that rules out E. None of the above
So there are Infinitely many solutions, No solutions, Or , 1 Unique Solution. In other words, Parallel Lines, The Same Line Overlapping, or Lines that cross Once... in a 2-D space, we aren't considering Skew lines here
So, lets take a look at the equations now
4x - 3y = 15 7y - 35 = 9 1/3x
is that 9 and 1/3 x?
yes sorry i wasnt sure how to type that mixed fraction.
that is right, just wondering if it is a mixed number for sure
\[9 \frac{ 1 }{ 3 }x\]
The easiest way to tell which case you have , is to try and solve the system. There are other ways that are quicker , i can tell you after trying to solve them first
okay let me try and solve it quickly
turn that mixed number to an improper fraction first, then multiply the whole equation by the denominator to get rid of the fraction
7y - 35 = 9 1/3x 7y - (28/3)x = 35 21y - 28x = 105 ----------------------- so the two equations w/o fractions are 4x - 3y = 15 -28x + 21y = 105
ok thats what i just got as well.
before solving, let me show you this neat trick
alright :)
well, actually no, try to solve first
okay one second.
i'm solving for x and y correct?
right, you could solve one for x or y, then substitute that into the second equation
4x - 3y = 15 -28x + 21y = 105
alright would x be 15/4 and y -5 ?
hmm, you must have gone wrong someplace... ill start going through, lets try to solve each one for y = mx + b first ok?
okay
4x - 3y = 15 3y = 4x - 15 ------------> y = (4/3)x - 15 -28x + 21y = 105 21y = 28x + 105 ----------> y = (4/3)x + 15 ------------------------------------------- The two equations are \[y = \frac{ 4 }{ 3 }x - 15~~~and~~~y=\frac{ 4 }{ 3}x+15\]
Any part of that you don't see how to do?
okay yeah that's what i was getting, except \[\frac{ 4 }{ 3 }x-5\]
so that's where i got the -5. i see what you did though
ok, this is another way to find the solution,... now that you have both in the form y = mx+b set y1 = y2 and solve for x , we do that because we are looking for a point (x,y) that will work in both equations. So Y in the first equation should equal Y in the second equation. Y = Y, replace with mx+b = mx+b and solve for x
\[\frac{ 4 }{ 3}x + 15 = \frac{ 4 }{ 3 }x - 15\]
what do you get for x when you solve that?
lets see. what if i don't get anything?
take off 4/3 x on both sides, you are left with 15 = -15 right?
That is a false statement. This means that there is NO SOLUTION (x,y) that will work in both equations.
you're right it would bring it down to 15=-15
From the two lines in y = mx+b form... y = (4/3)x + 15 y = (4/3)x - 15 what do you notice about the slopes (m), and the Y intercepts (b)
|dw:1420424679960:dw|
There are no solutions to the two equations. The solutions are where the two lines intersect (x,y). Here they are parallel, They have the same slope (4/3) but different y-intercpets +15 and -15
That is why when you tried to solve it, you got a nonsense answer like -15 = 15. That means there are no solutions, and the lines are parallel.
From the initial post i did with the definitions, Which one is this then? Inconsistent = no solutions to the system, no point (x,y) that satisfies both equations. They are Parallel lines. Dependent = There are infinitely many solutions to the system. This happens if both equations are the same line, they overlap at an infinite amount of points (x,y) Consistent = the lines cross at one point, and there is a unique solution (x,y) that satisfies the equations.
I will show you a faster way to do these problems now if you would like.
so it would solely be inconsistent then.
yep, inconsistent = no solutions -15 = 15 FALSE
Remember it like, if you get a dumb answer like 10 = 25 , obviously false, then another word for that is it is inconsistent.
Here is a fast way to tell if lines are either Parallel, or the Same Line (Inconsistent or dependent)..... 4x - 3y = 15 -28x + 21y = 105 Multiply the first equation by a constant number (-7), the system is then... -28x + 21y = -105 -28x + 21y = 105 Notice by multiplying the first equation by a constant (this doesnt change the equation at all if you do it to every term), the left hand side becomes identical for the 2
If you can multiply an equation by a constant, and the equation becomes the same left hand side, the lines are parallel.
We say , lines are parallel if one is a scalar multiple, in this case (-7) of the other line.
If you multiply through , and both sides of the equation becomes the same, then obviously you have the same line and they are dependent. For Example, Pretend the 15 in the first was a -15 4x - 3y = -15 -28x + 21y = 105 Now multiply the first equation again by (-7) and you get... -28x + 21y = 105 -28x + 21y = 105 Same exact equation, same line, dependent, infinite solutions
that is just a quicker way to tell real fast if you have parallel lines, or the same line written in 2 different forms.
Here is a little page i found to review if needed, going over each type of system... http://www.algebra.com/algebra/homework/coordinate/Types-of-systems-inconsistent-dependent-independent.lesson
if you have another one you want to run through for practice, tag me in
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