Ask your own question, for FREE!
Mathematics 19 Online
OpenStudy (waheguru):

Simplify this

OpenStudy (waheguru):

log100m - log(10/n)

OpenStudy (solomonzelman):

\(\large\color{slate}{ \log_{100}{\rm m} - \log(10) - \log (10/{\rm n} ) }\) \(\large\color{slate}{ \log_{100}{\rm m} - \log(10) - \log ({\rm n} ) }\)

OpenStudy (waheguru):

its not base 100 its log100m

OpenStudy (waheguru):

the base is 10

OpenStudy (solomonzelman):

\(\large\color{slate}{ \log100{\rm m} - \log(10) - \log ({\rm n} ) }\)

OpenStudy (solomonzelman):

Sure;)

OpenStudy (waheguru):

yea

OpenStudy (solomonzelman):

you aren't done simplifying

OpenStudy (waheguru):

this was a test question and it said which of the following is equavalent to this expression and I am given 5 options (im trying to fix my mistake as i got this wrong)

OpenStudy (solomonzelman):

what are the options?

OpenStudy (waheguru):

3+logm+log

OpenStudy (solomonzelman):

is that your answer?

OpenStudy (waheguru):

1+logm-logn

OpenStudy (solomonzelman):

and this is your ans?

OpenStudy (waheguru):

2+logm - logn -- this was my answer I guessed :S

OpenStudy (solomonzelman):

oh my man, I stinck

OpenStudy (triciaal):

when you subtract logs divide the numbers

OpenStudy (solomonzelman):

lol, yes it is that

OpenStudy (waheguru):

1+logm+logn and finally 3+logm-logn

OpenStudy (solomonzelman):

\(\large\color{slate}{ \log100{\rm m} - \log(10) - \log ({\rm n} ) }\) \(\large\color{slate}{ 2\log10 +\log{\rm m} - \log(10) - \log ({\rm n} ) }\) \(\large\color{slate}{ 1 +\log{\rm m} - \log ({\rm n} ) }\)

OpenStudy (solomonzelman):

dere u go

OpenStudy (waheguru):

oooh

OpenStudy (waheguru):

thanks

OpenStudy (triciaal):

|dw:1420423929620:dw|

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!