Question

Jim is building a model of a square pyramid for a class project. The side length of the square base is 12 inches and the slant height of the pyramid is 20 inches. What is the surface area of the model pyramid?

Answer 1

Hmm,what do u think? @tlashay11

Answer 2

@MARC_ how r u mate?

Answer 3

S.a = [Base Area] + 12 × Perimeter × [Slant Length]

Answer 4

refresh as you know

Answer 5

just guessing here but 436?

Answer 6

436 ?

Answer 7

than not right cause its not one of the answers

Answer 8

*thats

Answer 9

184 its not up there either

Answer 10

[Base Area] + 12 × Perimeter × [Slant Length] = 1/2 x [48] x [20] = 480 cm^3

Answer 11

Is that one of the answers?

Answer 12

\[=4(\frac{ 1 }{ 2 }\times12\times20)+(12\times12)\]
\[=480+144\]
\[=?\]
solve it @tlashay11

Answer 13

marc you r sticking to this formula

Answer 14

Do you understan d this formula?

Answer 15

but you do understand another formula, perpendicular base x height = triagle

Answer 16

this is area.

Answer 17

@tlashay11

Answer 18

http://www.mathopenref.com/pyramidarea.html

Answer 19

this might help u

Answer 20

Total Area
So the total surface area of the above pyramid is
Area of the base 100
Area of the four faces = 4 times 55 220
TOTAL 320
As a formula
Since the base of a pyramid can be any polygon, and you may be given various different measurements, it's best to follow the method above to find the area. But in the particular case of a right square pyramid with the base side and slant height given, the area is given by the formula Formula for the surface area of a pyramid Where b is the side length of the base, and h is the slant height.

By combining the 4 and the 2, this simplifies a little to The first one is better because it shows more clearly how it is made up from its parts - the base area plus four face areas.