Question

please help

find the general form of the equation of the line that passes through the given point and has the indicated slope.

(-2,0), m=-2/5

Answer 1

With \((-2~,~0)~,~ m=-\dfrac{2}{5}\) Use point slope form: \(y -y_1 = m(x-x_1)\)

Answer 2

So \((x_1~,~y_1) = (-2~,~0)\). Plug that into point slope form.

Answer 3

Then tell me what you get :)

Answer 4

(y-0)= 2/5 (x+2)

Answer 5

now what?

Answer 6

So the general form of the equation follows the format : \(ax +by +c=0\)

Right now, we have : \(y=\dfrac{2}{5}(x+2)\)

So I guess first we should distribute the \(\dfrac{2}{5}\). What do you have then?

Answer 7

y= 2/5x+4/5

Answer 8

Awesome, now just move everything to the left side.

Answer 9

Subtract \(-\dfrac{2}{5}x\) and \(-\dfrac{4}{5}\) from both sides of the equation. What do you end up with?

Answer 10

2/5x+4/5+y???

Answer 11

is that right, wrong................?

Answer 12

Not quite. you had \(y=\dfrac{2}{5}x+\dfrac{4}{5}\) and you want to fit the general form of the equation: \(ax+by+c=0\), so We would move everything over to the left side by subtracting \(-\dfrac{2}{5}x-\dfrac{4}{5}\) from both sides of he equation. We would end up with: \[\boxed{y-\dfrac{2}{5}x-\dfrac{4}{5} = 0}\]

Answer 13

We can also simplify this by multiplying both sides of the equation by \(5\) to get rid of the fractions.: \[5\left(y-\frac{2}{5}x -\frac{4}{5}=0\right) = \boxed{-2x+5y-4=0}\]

Answer 14

Do you understand @Romwil ?

Answer 15

oh sweet thanks

Answer 16

my answer sheet said it's all positive, but it's prob wrong