What is the range of the equation? I will add in a second!
\[\frac{ 1{} }{ \sqrt{x+4} }\]
@Jhannybean can you help me with this last one? :)
Or @Littlebird if im not annoying you haha
I already know that the domain is (-4, infinity)
Since x is in the denominator and under a square root, the y can never be negative or 0.
Well, if x=0, y = \(\frac{1}{2}\)
the options that i have to answer from are A) (Negative infinity,0) U (0, infinity) B) (Negative infinity, infinity) C) (0, infinity)
However, I this case, the range is definitely all positive real numbers (C)
|dw:1420436652168:dw|
@Littlebird wrote earlier: "Since x is in the denominator and under a square root, the y can never be negative or 0." This is correct. If y is not negative or zero, then y is non-negative.
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