6.Factorise the following expressions completely.
@ganeshie8
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OpenStudy (anonymous):
b) 9+7x-2x^2=
OpenStudy (anonymous):
\( A=-2x^2 + 7x + 9 \) then consider \( -2A = (2x)^2 - 7(2x) - 9(2) \) can u factorise this expression?
OpenStudy (anonymous):
=2x^2-14x-18
OpenStudy (anonymous):
are u sure u have copied the question completely?
OpenStudy (anonymous):
yep @PFEH.1999
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OpenStudy (anonymous):
yes it's correct ;)
OpenStudy (anonymous):
forget that way...
an awesome way is that find zeroes of that equation : \( A=-2x^2 + 7x + 9 \)
OpenStudy (anonymous):
What u mean by finding zeroes of that equation? @PFEH.1999
OpenStudy (anonymous):
find x in which A=0
OpenStudy (anonymous):
okay..let me think. :)
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OpenStudy (anonymous):
u can use quadratic formula.
OpenStudy (anonymous):
i got =(2x-9)(x+1) @PFEH.1999
OpenStudy (anonymous):
but the answer in my book said is (9-2x)(x+1) @PFEH.1999
OpenStudy (anonymous):
(9-2x) or (2x-9) is the same rite? @PFEH.1999
OpenStudy (anonymous):
u know the zeros are \( -1\) and \( \large \frac{9}{2}\) and if u put 9/2 in both equations you will get zero,but consider that in that equation the sign of \( x^2 \) was negative so ur factor should be negative too ;) i didn't notice that by mistake ;)
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