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The pyramid shown has a square base with sides (3y-4)cm and a vertical height of 6 cm.The total volume of the pyramid is 32cm^3. @sammixboo
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i got 18y^2-48y=0
this is my working
Wait what are you trying to find?
write down a quadratic equation in terms of y. sorry
\[\frac{ 1 }{ 3 }(6)(3y-4)^2=32\]
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\[2\left[ (3y-4)(3y-4) \right]=32\]
I believe that is correct from what I did. I just want a second opinion
\[2(9y^2-24y+16)=32\] \[18y^2-48y+32=32\]
Yes
I believe you are correct
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thnx @sammixboo :)
No problem :)
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