medal!!!! please help geometry
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Question

medal!!!! please help geometry
Pic below

anonymous · Answer

attachment

demonchild99 · Answer

ok look at the corresponding sides of the triangles..do you see any resemblance?

anonymous · Answer

im not to good at geo like at all): and i just came back from break

demonchild99 · Answer

lol...im not that good either...i never got to take a break..im just goin on what i can sorta remember..so please dont hate me if you get it wrong..ok?

anonymous · Answer

okay
 its cool

demonchild99 · Answer

ok ...now um...look at the sides of the triangle...i would say that the side with 21 and 7 are um..proportional....what can you do with those numbers?

demonchild99 · Answer

i believe you would divide them...and after that you get 3 correct?

demonchild99 · Answer

well what i did was i took three and divided 20 by it....calculate it what would that be

demonchild99 · Answer

@sleepyjess  am i doin this right?...help meh gurl

sleepyjess · Answer

This was 2 years ago, you expect me to remember this?

demonchild99 · Answer

well heck im doin this last year...im just not sure if i am rememberin correctly...lol....call one of your smart friends

anonymous · Answer

?

sleepyjess · Answer

ummmm maybe @iGreen ?

igreen · Answer

Okay..I'm guessing the triangles are similar..therefore we can set up  proportion:

$\dfrac{21}{7} = \dfrac{20-x}{x}$

Now we cross multiply, which gives us:

$21x = 140 - 7x$

Now can you solve that for 'x'? @callmechris99

anonymous · Answer

remember this :-
$\text{All right triangles are congruent }$
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anonymous · Answer

thus u would have
\dfrac{21}{20-x} = \dfrac{7}{x}

anonymous · Answer

okok

igreen · Answer

Can you solve this for 'x'?

$21x = 140 - 7x$

First add 7x to both sides..