PLEASE HELP!!!!!!! WILL GIVE MEDALS:) complete this statement: 40x^4a^2+16x^2a^3=8x^2a^2( )
@AnswerMyQuestions @Albany_Goon @amandanewsomm @butterflydreamer @bazel_e @bohotness @ChiefArnav @Abhisar
what do you think completes the statment?
4x^2 is a common factor....that's really all i have so far...
40x^4 a^2 + 16x^2 a^3 = 8x^2 a^2 ( ) so now equate this to zero imean do this 40x^4 a^2 + 16x^2 a^3 - 8x^2 a^2 = 0
now solve this equation
:)working on it....one moment:)
i have a question...why did you subtract the 8x^2?
as its positive on the side it belongs so on changing the side it becames negative
okay...
hint: Common factor: 8x^2a^2
not sure if this is right but here's where i'm at 10x^2a^24xa^3-4xa^2=0
thats wrongs
look at the hint i gave you and the equation
you can't do 8x because it's not a multiple of 40...
just kidding. i'm wrong. sorry!
so what did you get now?
8 times 5 is 40 -_-
10x^2a^24xa^3-4xa^2=0
and i know, horrible at math, sorry.
scroll back up and look at the very first reply of mine...
i'm so confused now..i'm sorry just looked at it. what'd i do wrong?
ummmm....? sorry to say but we will have begin all over again.. -_-
why?
40x^4 a^2 + 16x^2 a^3 = 8x^2 a^2 ( ) so now equate this to zero imean do this 40x^4 a^2 + 16x^2 a^3 - 8x^2 a^2 = 0
now take 8x^2 a^2 as a common factor
can you just give me the answer? i don't have enough time to do it again...it's a timed thing.
@bohotness do you know the answer?
8x^2a^2[5x^2 + 2a - 1] is the answr
answer*
he is right:)
nd yes i do known the answer
okay so thats wrong...the correct answer was 5x^2+2a but thank you for your help anyways.
\[40x^{2}a ^{2}+16x^{2}a ^{3} divide 8x ^{2}a ^{2}
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