Help!!

A business bought computers for its company for $350,000 two years ago. What is the value of the company's computers in three years using the depreciation rate of 23%?

A. $94,737.45
B. $159,786.55
C. $207,515.00
D. $311,559.40

Question

Help!!


A business bought computers for its company for $350,000 two years ago. What is the value of the company's computers in three years using the depreciation rate of 23%?

	A.     $94,737.45
	B.	$159,786.55
	C.	$207,515.00
	D.	$311,559.40

anonymous · Answer

$$A=350,000\left( 1-\frac{ 23 }{ 100 } \right)^5=?$$

anonymous · Answer

Do you do what's in parthenesis first?

anonymous · Answer

350,000 * (1-.23)=350,000*.77=269,500    first year
269,500*,77=207,515   2 year
207,515*.77=159,785,55

anonymous · Answer

=159,786.55

anonymous · Answer

so it is B

anonymous · Answer

basically the total lowers by 23 percent each year for 3 years.... so first year 350,000 x .77  = x   next year x times .77  = y and final year y times .77 = ending amount  i put .77 bc since its 23 percent your total would be 77 percent of it.

anonymous · Answer

hence the answer is B

anonymous · Answer

Thamk you so much! I'm not the best at this whole thing. I think I understand the problem more.

anonymous · Answer

$$A=price (1-depre%)^{number of years}$$