Mathematics
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OpenStudy (anonymous):
Simplify sec^2 x - 2 - tan^2 x
11 years ago
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OpenStudy (anonymous):
Sec^2 - (sin^2 + cos^2) - (sin^2 + cos^2) - (sin/cos)^2 ?
11 years ago
OpenStudy (anonymous):
( Sec - (sin + cos) - (sin + cos) - (sin/cos) )^2
11 years ago
OpenStudy (anonymous):
@SolomonZelman
11 years ago
OpenStudy (solomonzelman):
\(\large\color{slate}{ \sec^2x -2-\tan^2x }\). And you need to simplify this?
11 years ago
OpenStudy (anonymous):
sec^2 x - 2 = tan^2 x sorry
11 years ago
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OpenStudy (anonymous):
Then find the solutions
11 years ago
OpenStudy (solomonzelman):
\(\large\color{slate}{ \sec^2x -2=\tan^2x }\)
11 years ago
OpenStudy (anonymous):
Which shouldn't be too hard after the problem is simplified
11 years ago
OpenStudy (anonymous):
Yes that is the problem
11 years ago
OpenStudy (solomonzelman):
apply: \(\large\color{red}{ \sec^2x=\tan^2x+1 }\)
11 years ago
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OpenStudy (anonymous):
Ok I will
11 years ago
OpenStudy (anonymous):
tan^2 x - 1 - tan^2 x ?
11 years ago
OpenStudy (anonymous):
Then -1
11 years ago
OpenStudy (solomonzelman):
\(\large\color{slate}{ \tan^2x -1=\tan^2x }\) ?
11 years ago
OpenStudy (solomonzelman):
that is what you meant?
11 years ago
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OpenStudy (anonymous):
tan^2 x - 1 - tan^2 x = 0
11 years ago
OpenStudy (solomonzelman):
yes, and simplify the left side
11 years ago
OpenStudy (anonymous):
How?
11 years ago
OpenStudy (solomonzelman):
\(\large\color{slate}{ \tan^2x -1-\tan^2x=0 }\)
something cancels.....
11 years ago
OpenStudy (anonymous):
Tan^2
11 years ago
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OpenStudy (solomonzelman):
yes
11 years ago
OpenStudy (anonymous):
So -1 = 0
11 years ago
OpenStudy (anonymous):
Then -(sin^2 x + cos^2 x) = 0?
11 years ago
OpenStudy (solomonzelman):
no, once you get \(\large\color{slate}{ -1=0 }\), that means that there is no solution
11 years ago
OpenStudy (anonymous):
Thanks! It makes sense.
11 years ago
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OpenStudy (solomonzelman):
Oh, I opened my profile and saw that you finished typing and this last reply. In my post-tab it said that you were typing still..... anyways, you welcome!
11 years ago