Question

An architect for a golf course wants to plan a sand trap that passes between a tree and a cart path. Using these as the focus and directrix, how can the architect plan a parabolic sand trap that will be equidistant from the tree and the cart path at all times? Describe your method in full sentences.

Answer 1

@morganmay19

Answer 2

idk

Answer 3

xc ok...

Answer 4

@HelpBlahBlahBlah

Answer 5

I'm sooooo bad at parbola's and this stuff, hang on.

Answer 6

I'm sorry I have no idea :/

Answer 7

OHHMAIIIGERDD!

Answer 8

have you tried google?

Answer 9

No, I want to know how to do it, not just the answer.

Answer 10

okay hold on

Answer 11

The trap should coincide with the curve of the parabola, the vertex of which would be half between the tree and the cart path.The equation would be given as
y= a(x-h)^2+k, where (h,k) is the vertex and (x,y)is the coordinate of any point on the parabola. If the focus is at (Fx,Fy) and the direction is y,
p=1/2(Fx-y)
and
a=1 / 4p

or

a=1/4[1/2(Fx-y)]
a=1/2(Fx-y)

so
The equation of the sand trap is given by
y=[1/2(Fx-y)] (x-h)^2+k

Answer 12

Thanks a lot @lexikaylynn xD

Answer 13

your welcome :D