I need help , give me an idea o this one please Figure on comments
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I don't get it! Please explain! We need the dimension of the two legs, and have to assume the included angle is 90 deg.
yeah , thats what Im troubled about. Its Two sides of a square are along the lines whose equations are 4x-3y =25 and 4x-3y = -10. What is the perimeter of the square? So thought of solving the hypotenuse( diagonal ) and use formula for the perimeter 4 d
@mathmate
ok, this is a completely different problem! The triangle misled me.
sorry about that hehe
First we'll draw a sketch!
alright :)
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oh so thats how it looks like
please continue :)
The two lines have the same slope, so they are parallel.
To find the perimeter of the square, you need the length of one side.
alright ...
Would you be able to propose how we can go about finding it?
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transform it to y = mx + b , form ? or get the coordinates and use point slope form ?
It's actually easier than that. I have already done the first step, which is to transform the equations to the general form: Ax+By+C=0.
Have you learned how to find the distance between a \(point\) and a \(line\)?
I think Im familiar with that
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