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Mathematics 21 Online
OpenStudy (yamyam70):

I need help , give me an idea o this one please Figure on comments

OpenStudy (yamyam70):

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OpenStudy (mathmate):

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OpenStudy (yamyam70):

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OpenStudy (mathmate):

I don't get it! Please explain! We need the dimension of the two legs, and have to assume the included angle is 90 deg.

OpenStudy (yamyam70):

yeah , thats what Im troubled about. Its Two sides of a square are along the lines whose equations are 4x-3y =25 and 4x-3y = -10. What is the perimeter of the square? So thought of solving the hypotenuse( diagonal ) and use formula for the perimeter 4 d

OpenStudy (yamyam70):

@mathmate

OpenStudy (mathmate):

ok, this is a completely different problem! The triangle misled me.

OpenStudy (yamyam70):

sorry about that hehe

OpenStudy (mathmate):

First we'll draw a sketch!

OpenStudy (yamyam70):

alright :)

OpenStudy (mathmate):

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OpenStudy (yamyam70):

oh so thats how it looks like

OpenStudy (yamyam70):

please continue :)

OpenStudy (mathmate):

The two lines have the same slope, so they are parallel.

OpenStudy (mathmate):

To find the perimeter of the square, you need the length of one side.

OpenStudy (yamyam70):

alright ...

OpenStudy (mathmate):

Would you be able to propose how we can go about finding it?

OpenStudy (mathmate):

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OpenStudy (yamyam70):

transform it to y = mx + b , form ? or get the coordinates and use point slope form ?

OpenStudy (mathmate):

It's actually easier than that. I have already done the first step, which is to transform the equations to the general form: Ax+By+C=0.

OpenStudy (mathmate):

Have you learned how to find the distance between a \(point\) and a \(line\)?

OpenStudy (yamyam70):

I think Im familiar with that

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