Question

A plane starting at rest at the south end of a runway undergoes a constant acceleration of 1.6 m/s/s for a distance of 1600m before takeoff.
Part 1: What is the time required for takeoff?
Part 2: What is the plane’s velocity at takeoff?

**How do we solve these ones? @michele_laino? :)

Answer 1

please you have to apply this formula:
\[S=\frac{ 1 }{ 2 }a*t ^{2}\]
where S=1,600 meters and a=1.6 m/sec^2
please solve that equation for t

Answer 2

okay! so
1600=1/2(1.6)*t^2
1600=0.8 * t^2
2000=t^2
t=44.72 ? :/

Answer 3

that's right!

Answer 4

yay! :)

so that's part 1 correct?

what about part 2? :/

Answer 5

for part 2 you have to apply this formula:
\[v(t)=a*t\]
where t is 44.72 sec and a=1.6 m/sec^2

Answer 6

ah okie!

so v(t)= 44.72 * 1.6 = 71.55 m/s ?

Answer 7

that's right!

Answer 8

awesome!! thank you:)

Answer 9

thank you!! :)