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Find the volume (in liters) of 41 moles of gas under 4 atmospheres at 159k. (PV=nRT with R=0.0821) A. 535.21 L B. 133.802 L C. 12.5633 L D. 1.27355 L E. none of these
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PV=nRT so V=\(\frac{nRT}{P}\)
so we are given 4 knowns and we are solving for 1 uknown the volume of the gas so we can pug these numbers in like this 4atm(X)=41moles(.0821)(159Kelvins)
so the problem i need to solve would be 41(.0821)(159) ?
that gave me 535.2099 which i would assume to round up to 535.21
that divided by 4 so (41(.0821)(159))/4
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u have to divide by 4!
okay so that divided by 4 would bring me to 133.802 ?
imma check your answer real quick
okay thank you.
yes 133.802 Liters is the correct answer nice work
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thank you :)
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