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Mathematics 22 Online
OpenStudy (anonymous):

Can someone explain extraneous and non-extraneous to me, thanks.

OpenStudy (alexandervonhumboldt2):

extraneus are solution that dont fit in th eqaution non ones ar opposite

OpenStudy (anonymous):

yeah but what does it mean if it doesn't fit

OpenStudy (anonymous):

??

OpenStudy (alexandervonhumboldt2):

extraneus means it doesnt fit

OpenStudy (anonymous):

ok im still confused

OpenStudy (alexandervonhumboldt2):

non-extraneus means it fits the equation

OpenStudy (anonymous):

yeah but what do you mean it doesn't fit

OpenStudy (anonymous):

example would be helpful

OpenStudy (alexandervonhumboldt2):

@iambatman

OpenStudy (anonymous):

@iambatman ??

OpenStudy (alexandervonhumboldt2):

she wants n expmple i cant do thats can you?

OpenStudy (anonymous):

Here is a good definition that I always thought about when thinking about this, here's the link https://www.mathsisfun.com/definitions/extraneous-root.html

OpenStudy (anonymous):

Err this is for math right haha?

OpenStudy (anonymous):

yeah for algebra 2 lol

OpenStudy (anonymous):

Alright was just wondering since it's on the history section :P

OpenStudy (anonymous):

wait what this the history section?

OpenStudy (anonymous):

Yup! No worries though, anyways did that definition make sense?

OpenStudy (anonymous):

that's weird bc i closed out of the history section a long time ago but ok

OpenStudy (anonymous):

and yeah it makes sense kinda

OpenStudy (anonymous):

The one you may see a lot for a example is \[\sqrt{x} = -3\] so now if you square both sides \[(\sqrt{x})^2 = (-3)^2 \implies x = 9~~~~\sqrt{9} \neq -3\] so it's a extraneous solution

OpenStudy (anonymous):

ohhh so basically it has to equal to zero when x gets plugged back into the equation and that will make it non-extraneous?

OpenStudy (anonymous):

*to be equal to

OpenStudy (anonymous):

Not really sure what you mean, but extraneous root can be thought of as an answer that is not the "true answer" but still can be correct, if that makes sense.

OpenStudy (anonymous):

From that link it says "When you put "a" into the original equation it becomes zero, but when you put in "b" it doesn't. So "b" is an extraneous root."

OpenStudy (anonymous):

So when a is plugged back into the equation it equals zero so that means it's non-extraneous right??

OpenStudy (anonymous):

@iambatman

OpenStudy (anonymous):

That's just one example, it's not always the case, as I presented above.

OpenStudy (anonymous):

im still confused so what makes an equation non-extraneous??

OpenStudy (anonymous):

non - extraneous would be the right solution upon checking the solution.

OpenStudy (anonymous):

Also, my title just changed to mathematics so I guess you're in the right section and my OS was messed up :P

OpenStudy (anonymous):

\[ \frac{ 4 }{ x+2 }=\frac{ 2 }{ x}\] how would i solve for x and determine if the root is extraneous or not?

OpenStudy (anonymous):

@SolomonZelman

OpenStudy (anonymous):

@ganeshie8

OpenStudy (anonymous):

help someone

OpenStudy (anonymous):

anyone

OpenStudy (anonymous):

@satellite73

OpenStudy (anonymous):

@e.mccormick

OpenStudy (anonymous):

nobody.wants.to.help.me.

OpenStudy (anonymous):

this.is.awesome.

OpenStudy (anonymous):

not

OpenStudy (anonymous):

helppppppppppppppppppppppp

OpenStudy (anonymous):

:(((((((((((

OpenStudy (anonymous):

@jdoe0001

OpenStudy (anonymous):

@mathstudent55

OpenStudy (anonymous):

this sucks

OpenStudy (anonymous):

no help

OpenStudy (anonymous):

im talking to myself

OpenStudy (anonymous):

this is gr8

OpenStudy (anonymous):

What have you tried?

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