Question

Heights of certain plants at a nursery are normally distributed with a mean of 45.3 centimeters and a standard deviation of 6.6 centimeters. If their z-scores are greater than 1.75, the plants are displayed in the main lobby. To the nearest centimeter, what is the minimum required height for this type of plant to be displayed in the main lobby? 49 cm 50 cm 56 cm 57 cm

Answer 1

@DanJS

Answer 2

z=X−μσ

Plugging the given values into the above equation, we get:
1.75=X−45.36.6

Now you need to solve to find the value of X.

Answer 3

Hint:
Z=(X−μ)/σ

Answer 4

i got 49 cm

Answer 5

:0

Answer 6

@Pamela16
I don't get the same number as you, would you like to check?

Answer 7

give me a second

Answer 8

i keep getting 49 or 56

Answer 9

Why 49 or 56? Did your calculator give you two numbers? lol

Answer 10

Use Google I Mmm an if it helps

Answer 11

Mean

Answer 12

\(\large 1.75=\frac{X-45.3}{6.6}\)
\(\large 1.75\times 6.6=X-45.3\)
\(\large (1.75\times 6.6) + 45.3=X\)

Answer 13

i got 56.85

Answer 14

And if you round it, what do you get?

Answer 15

57

Answer 16

Itry again

Answer 17

So which choice do you take?

Answer 18

Remmber another 5 and up goes up and then 4 and down goes down

Answer 19

d.57

Answer 20

Correct!
\(\color{blue}{\Large\checkmark}{Way~to~go!}\)

Answer 21

????nvm

Answer 22

how about this one
In a standard normal distribution, above which z-score do approximately 63% of the data lie?
(Points : 4)
1.79

0.33

-0.33

-1.79

Answer 23

Which one do you think is your answer

Answer 24

im not really sure

Answer 25

Take a guess

Answer 26

-0.33?

Answer 27

Okay

Answer 28

correct?

Answer 29

Holdon I dont its right @mathmate

Answer 30

Ok, let's see!
@Pamela16

Answer 31

Since normal distribution tables refer to percentage of data to the left, and question says 63% above (to the right), we need the % below (to the left).

Answer 32

0.33?