Question

Check my answer?
Simplify: 4i^4 -3i^3 -sqrt-3 sqrt3
A. 3-3i^3 +4i^4
B. 7+3i
C. 4-6i
D. 4i
E. none of these

I'm getting D. 4i ?

Answer 1

@Nnesha

Answer 2

This is the property
\[i^2 = -1~~~or~~~i=\sqrt{-1}\]

Answer 3

i = i
i^2 = -1
i^3 = i^2 *i = -1*i
i^4 = i^2 *i^2 = -1 * -1 = 1

The cycle repeats
i
-1
-i
+1

Answer 4

\[4i^4-3i^3-\sqrt{-3}\sqrt{3}\]

Did i get that right?

Answer 5

\[4 * i^2*i^2 - 3*i^2*i - \sqrt{-1}\sqrt{3}\sqrt{3}\]

replace all i^2 by -1 ,
all root -1 by i

Answer 6

rot -1 is i^2

Answer 7

Okay so far it looks like how i did it.

Answer 8

4*-1*-1 - 3*-1 *i - i^2 *3

4 + 3i -3i^2

4 + 3i - 3*-1

4 + 3i + 3

7 + 3i

Answer 9

you see each part?

Answer 10

yess, i see each part.

Answer 11

i think i went wrong on the 3rd step somehow

Answer 12

just treat these like normal probs with the 'i' being a normal variable, then just use the property that i^2 = -1 or square root of -1 = i

Answer 13

okay ill write that tip down. thank you :)

Answer 14

welcome